Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 1 (Q.No. 2)
2.
When a body moves with simple harmonic motion, the product of its periodic time and frequency is equal to
Discussion:
15 comments Page 2 of 2.
Deepakdixit said:
1 decade ago
T = 1/f.
So 1 = tf.
So 1 = tf.
Gudipalli kiran kumar said:
1 decade ago
In simple harmonic motion.
Time period= 2 pi /omega seconds.
Frequency= omega/2 pi rad/seconds.
So product of reciprocals is ONE.
Time period= 2 pi /omega seconds.
Frequency= omega/2 pi rad/seconds.
So product of reciprocals is ONE.
Asadullah hashmi said:
1 decade ago
Here asked that the product of frequency and time.
T=1/f.
f=1/T.
f*T=1/f*1/T=1 Answer.
T=1/f.
f=1/T.
f*T=1/f*1/T=1 Answer.
Mahaveer said:
1 decade ago
Because T=1/f and f=1/T hence T. F=1.
Gowthaman said:
1 decade ago
T = 1/f.
Where,
T = Time.
f = Frequency.
Where,
T = Time.
f = Frequency.
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