Mechanical Engineering - Theory of machines - Discussion

Discussion Forum : Theory of machines - Section 1 (Q.No. 2)
2.
When a body moves with simple harmonic motion, the product of its periodic time and frequency is equal to
zero
one
π/2
π
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Gudipalli kiran kumar said:   1 decade ago
In simple harmonic motion.

Time period= 2 pi /omega seconds.

Frequency= omega/2 pi rad/seconds.

So product of reciprocals is ONE.

Parashugouda@gmail said:   9 years ago
@Shailesh Chavada.

Simple harmonic motion means motion of a particle moving along a straight line with an acceleration.
(1)

Asadullah hashmi said:   1 decade ago
Here asked that the product of frequency and time.

T=1/f.
f=1/T.
f*T=1/f*1/T=1 Answer.

ANKOSH said:   7 years ago
Time period=T=2π/ω.
Frequency=omega /2π.
then,
time*frequency=1.
(6)

Varun Yadav said:   10 years ago
Time = 1/frequency.

=> Time*frequency = 1/frequency*frequency = 1.

ADD said:   9 years ago
Time = 1/frequency.

Time * frequency = 1/frequency * frequency = 1.

Karthik Patel Edidhineni said:   1 decade ago
Periodic time is reciprocal of frequency. So the answer is 1.

Mahadev Patil said:   9 years ago
T=2π/w and f=w/2π.

Then, T * f = 1.

Gowthaman said:   1 decade ago
T = 1/f.

Where,

T = Time.
f = Frequency.

Shailesh Chavada said:   9 years ago
How you can define simple harmonic motion?


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