Mechanical Engineering - Theory of machines - Discussion

Discussion Forum : Theory of machines - Section 4 (Q.No. 9)
9.
Which of the following statement is wrong?
A round bar in a round hole form a turning pair
A square bar in a square hole form a sliding pair
A vertical shaft in a foot step bearing forms a successful constraint
all of the above
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Ajay anand said:   5 years ago
Partially turning and partially sliding so option A is correct.
(1)

Ajay anand said:   5 years ago
Option D is correct because above all options are true.

Ajay anand said:   5 years ago
Form Cylindrical pair so option A is correct.

Rajesh Kumar Kushwaha said:   6 years ago
Option (A) , as it forms Turing as well as translation motion. Which is unconstrained motion?

Updesh yadav said:   7 years ago
Round bar in round hole form a sliding pair this is the case of IC engine.

Nirmalendu Karak said:   7 years ago
In a turning pair also has a completely constrained motion.

Pramod said:   7 years ago
Option A is correct.

As we know that turning pair is equivalent to Revolute pair. It includes 1 DOF due to only rotation motion. But here, round bar can be either slide or rotate in the round hole. So, it is a cylindrical pair includes 2 DOF.
(1)

Dnd said:   8 years ago
Answer C is right Ref: Khurmi book Q10.
(1)

SACHIN CHAUHAN said:   8 years ago
Because turning pair is a kinemetic pair.

So kinemetic is only completely constrained motion.

Sagar vyavahare said:   8 years ago
Turning with sliding pair.


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