Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 7 (Q.No. 46)
46.
According to Euler's column theory, the crippling load for a column of length (l) with one end fixed and the other end hinged, is
Discussion:
5 comments Page 1 of 1.
Mahesh said:
10 months ago
Euler's column formula for a column with one end fixed and the other end hinged is;
[ P_{cr} = frac{{ π^2 cdot E cdot I}}{{(l_{eff})^2}}]
Where:
- ( P_{cr} \) is the critical buckling load (crippling load),
- ( E ) is the modulus of elasticity of the material,
- ( I) is the minimum moment of inertia of the column's cross-sectional area,
- ( l_{eff} ) is the effective length of the column.
[ P_{cr} = frac{{ π^2 cdot E cdot I}}{{(l_{eff})^2}}]
Where:
- ( P_{cr} \) is the critical buckling load (crippling load),
- ( E ) is the modulus of elasticity of the material,
- ( I) is the minimum moment of inertia of the column's cross-sectional area,
- ( l_{eff} ) is the effective length of the column.
Gopal Gawande said:
3 years ago
Correct answer will be B.
Paby said:
7 years ago
Answer is correct.
B is for one end fixed other end free.
B is for one end fixed other end free.
Vaibhavi barahate said:
7 years ago
Yes, The answer is B.
Galav said:
7 years ago
The answer is B.
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