Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 9 (Q.No. 49)
49.
The limit of eccentricity for no tensile conditions for a column of circular section of diameter (d) is
Discussion:
7 comments Page 1 of 1.
Subrata ghorai said:
3 years ago
P/A=P*e*y/I.
e = I/y*A p is cut if pis equal on both sides.
e=z/A.
For circle equation z=π*d cube/32.
A= π*d square /4.
Or calculate value of e we get D/8.
Or rectangle D/6
Thank you
e = I/y*A p is cut if pis equal on both sides.
e=z/A.
For circle equation z=π*d cube/32.
A= π*d square /4.
Or calculate value of e we get D/8.
Or rectangle D/6
Thank you
(1)
Rashid khan kakar said:
3 years ago
D/4 is the correct answer for no tension condition.
Vishal Kumar said:
5 years ago
But why should we take d/8 even d/12 the circle when in eccentricity? Explain.
Srilakshmi said:
8 years ago
e< or equal to d/8.
Pratik said:
8 years ago
Hi @Pranali.
It should be between diameter D/4 but in the question Eccentricity is asked which is nothing but radius which means D/8.
It should be between diameter D/4 but in the question Eccentricity is asked which is nothing but radius which means D/8.
RAj said:
8 years ago
How? Explain anyone.
Pranjali said:
9 years ago
D/4 is answer.
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