Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 9 (Q.No. 14)
14.
For no tension condition in the base of a short column of circular section, the line of action of the load should be within a circle of diameter equal to __________ of the main circle.
Discussion:
9 comments Page 1 of 1.
Sipun Patra said:
4 years ago
Right @Vipsai.
Hardik said:
4 years ago
Eccentricity =one side distance from centre.
=D/8 (radius).
For dia. to make circle= D/8 + D/8.
= D/4.
=D/8 (radius).
For dia. to make circle= D/8 + D/8.
= D/4.
Vipsai said:
5 years ago
We all know that Limit of Eccentricity for a circle is D/8 on either side of the Y-Y axis, which means D/8 + D/8 = D/4.
So, the load is limited to the radius of D/4 of the circle.
So, the load is limited to the radius of D/4 of the circle.
NITESH KUMAR said:
6 years ago
Right, agree @Subham Verma.
Subham verma said:
6 years ago
The answer will be C.
As we know, e less than or equals to d/8 for the circular section.
and as e is distance b/w centre line and max. possible pt. of no tension condition
therefore, e=r for that assumed circular section.
And r less than or equals to d/8.
Which implies r' = d/8 or d = d/4.
As we know, e less than or equals to d/8 for the circular section.
and as e is distance b/w centre line and max. possible pt. of no tension condition
therefore, e=r for that assumed circular section.
And r less than or equals to d/8.
Which implies r' = d/8 or d = d/4.
(1)
Naveen said:
6 years ago
The Answer should be D/8, which means 1/8. S, Option D is correct.
R H said:
7 years ago
I agree @Anirudh.
(1)
Parmar said:
8 years ago
I think it's for eccentric loading.
Anirudh said:
1 decade ago
The area where if force acts, no tensile force is created is called Kern area. It is d/4 (circular area) for a circular column and diamond (diagonals d/3 & d/3) for a rectangular column.
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