Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 6 (Q.No. 31)
31.
The maximum shear stress in a thin spherical shell subjected to an internal pressure (p) is zero.
Discussion:
7 comments Page 1 of 1.
SURAJ PRASAD KESHARI said:
4 years ago
Maximum share stress =(α1_α3)/2.
α1=α2 =pd/2t.
Because spherical shell stress under hoop stresses.
α1=α2 =pd/2t.
Because spherical shell stress under hoop stresses.
Pushpendra said:
6 years ago
Shear stress max. in 2d plane is zero.
But shear stress max. in absolute = [pd/4t -p], [pd/4t], [0].
But shear stress max. in absolute = [pd/4t -p], [pd/4t], [0].
(1)
Rajkotha said:
6 years ago
In sphere shear, stress is zero.
In cylinder shear, stress is pd/8t.
In cylinder shear, stress is pd/8t.
Neeraj said:
9 years ago
In plain is zero and outer is = σ/2.
Yogesh panchal said:
6 years ago
How it will be zero? Explain.
Mohan said:
5 years ago
((Pd/4t)-(pd/4t))/2 = 0.
(1)
Manish said:
7 years ago
How it will be zero?
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