Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 46)
46.
The strain energy stored in a solid circular shaft subjected to shear stress (τ) is (where C = Modulus of rigidity for the shaft material)
x Volume of shaft
x Volume of shaft
x Volume of shaft
x Volume of shaftDiscussion:
38 comments Page 2 of 4.
ABHIUSHEK said:
10 years ago
Answer D only applicable when the shaft is under torsion. So here it is not perfect and answer B is correct.
Ramesh Babu said:
1 decade ago
Yes option D is for strain energy stored in the material when it is subjected to torsional stress.
Mukesh kushwaha said:
10 years ago
The strain energy due to shear stress is answer B. Answer D is strain energy due to torsion.
PRAKASH SINGH said:
9 years ago
Opt is B, because shear stress is given not a torsional stress so, the right answer is B.
Sridevi said:
9 years ago
Answer is b because it is given as only shear is applied on shaft. Not torque.
Bunnnysunny said:
9 years ago
Guys, I think option B is correct. Option D is for torsional resilience.
Er. Aman said:
9 years ago
Shear stress is due to torsion. So, d is correct. Refer the text book.
Vijay kumar said:
10 years ago
Torsion energy = 1/2 * T * angle of twist.
So, option D is correct.
So, option D is correct.
Vanraj Gajarotar said:
9 years ago
Right answer is B, Option D is for shaft subjected to pure torque.
SARABJEET SINGH SANDHU said:
10 years ago
But torsion occurs due to shear force. So o0tion (D) is correct.
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