Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 46)
46.
The strain energy stored in a solid circular shaft subjected to shear stress (τ) is (where C = Modulus of rigidity for the shaft material)
x Volume of shaft
x Volume of shaft
x Volume of shaft
x Volume of shaft
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
38 comments Page 2 of 4.

Abhilash said:   8 years ago
Option B is the correct answer.

Joy Mandal said:   8 years ago
B is the correct answer. D is the strain energy due to torsion.

Teja Reddy said:   8 years ago
Answer is option B.

The strain energy stored in a solid circular shaft in torsion, subjected to shear stress (τ) , is:τ2/ 4G * Volume of the shaft.

Aakash said:   8 years ago
D is not a correct answer, Option B is the correct answer.
U = 1/2(T.θ)
U = 1/2(T^2L/GJ)
U = (τ^2/2G)Volume of shaft.

Gaurav said:   8 years ago
The Answer will be D. I agree with the given answer.

Robiii said:   8 years ago
A given shaft which is subjected to shear stress so defini torsion will be developed no need to mention in a question.

Deep said:   7 years ago
The correct Answer will be option B.

Jay prakash saini said:   7 years ago
Option B is correct.

Vinod said:   5 years ago
OPTION B Is true when;

The strain energy stored in a solid circular shaft subjected to shear stress (Ï„) is (where C = Modulus of rigidity for the shaft material).

Option D is true when,
The strain energy stored in a solid circular shaft subjected to torsion (T) is (where C = Modulus of rigidity for the shaft material).

Vanraj Gajarotar said:   9 years ago
Right answer is B, Option D is for shaft subjected to pure torque.


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