Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 8 (Q.No. 42)
42.
The polar modulus for a hollow shaft of outer diameter (D) and inner diameter (d) is
Discussion:
6 comments Page 1 of 1.
Niwash said:
5 years ago
Polar modulus= polar moment of inertia/R.
Polar moment of inertia= Ixx + Iyy =π/32*d4.
Polar moment of inertia= Ixx + Iyy =π/32*d4.
Debasish said:
7 years ago
Polar modus means torsional section modulus. So answer C is correct.
DEEPAK said:
7 years ago
Option c is correct @Amit.
Debashis said:
7 years ago
Option C is correct.
Amit said:
7 years ago
Option D is correct because polar modulus=J/R={&pie;*(D^4-d^4)/64}*2/D=&pie;*(D^4-d^4)/32D.
Sandip said:
8 years ago
The correct answer is D.
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