Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 15)
15.
The polar modulus for a solid shaft of diameter (D) is
Discussion:
8 comments Page 1 of 1.
Vishnu t said:
6 years ago
Polar modulus is also called section modulus so,
zp=j/c;
We know that j= πd^4/32,
c=r=d/2;
Substitute c we get,
The answer Z = πd^3/16.
zp=j/c;
We know that j= πd^4/32,
c=r=d/2;
Substitute c we get,
The answer Z = πd^3/16.
(1)
Maheshprasath said:
7 years ago
((3.14*D^4)/32) is a correct answer.
Lokesh d said:
8 years ago
For hollow shaft j?
Abhiram reddy said:
8 years ago
Polar modulus also called as section modulus of the shaft. It can be denoted by Z.
Z = I/Y.
I= πd4/32,
Y=d/2.
Z = πd4/32/d/2,
Z = πd3/16.
Z = I/Y.
I= πd4/32,
Y=d/2.
Z = πd4/32/d/2,
Z = πd3/16.
(2)
RUSHI said:
1 decade ago
Polar moment of inertia (J) = Pi/2*(R^4).
= Pi/32 D^4.
= Pi/32 D^4.
SUMIT said:
1 decade ago
Section modulus = PI/32*D^3/D/2.
= PI/16*D^2.
So right answer is Pi/16*d^2.
= PI/16*D^2.
So right answer is Pi/16*d^2.
Babubhilar said:
1 decade ago
Polar modulus = section modulus(j)/radius(d/2).
= pi/32*d^4/ d/2.
On solving we get pi/16*d^3.
= pi/32*d^4/ d/2.
On solving we get pi/16*d^3.
Shekhu said:
1 decade ago
Polar modulus = j/r.
J = pi*d^4/32.
R = d/2.
J = pi*d^4/32.
R = d/2.
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