Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 7 (Q.No. 19)
19.
Two solid shafts 'A' and 'B' are made of the same material. The shaft 'A' is of 50 mm diameter and shaft 'B' is of 100 mm diameter. The strength of shaft 'B' is __________ as that of shaft A.
Discussion:
11 comments Page 1 of 2.
MUHAMMAD NABI said:
4 years ago
As we know the strength of the shaft is measured by polar modulus.
Polor modulus = j/r.
Here solid shaft is given so for the solid shaft.
π/16 (d) ^3.
Now as db =100.
And da=50.
So.
π/16 (db) ^3 divide by pi/16 (da) ^3.
After a cancellation we get.
(db/da) ^3.
= (100/50) ^3.
= (2) ^3.
=8.
Polor modulus = j/r.
Here solid shaft is given so for the solid shaft.
π/16 (d) ^3.
Now as db =100.
And da=50.
So.
π/16 (db) ^3 divide by pi/16 (da) ^3.
After a cancellation we get.
(db/da) ^3.
= (100/50) ^3.
= (2) ^3.
=8.
Needo said:
4 years ago
@Yatheesh,
It's of the shaft, So option B is right.
It's of the shaft, So option B is right.
Yatheesh said:
6 years ago
Answer is 1/8.
Naresh said:
8 years ago
Thanks @Aabreeque and @Roshan.
Krunal degamadiya said:
8 years ago
It should be 1/8 times.
Satyabrata said:
8 years ago
Yes, torque solid shaft formula is used to get the answer.
Abreeque said:
9 years ago
M/sigma = z, and z = i/y.
= pi * d^4/64/d/2,
= pi * d^3/32,
So, z1/z2 = d1^3/d2^3.
= (50/100)^3
= (1/2)^3 = 1/8.
= pi * d^4/64/d/2,
= pi * d^3/32,
So, z1/z2 = d1^3/d2^3.
= (50/100)^3
= (1/2)^3 = 1/8.
NwosuKC said:
9 years ago
Not clear, please explain in detail.
Roshan said:
10 years ago
Here torque formula is used to compare their strength. As we know that torque is directly proportional to d^3 of the shaft.
Raheem said:
1 decade ago
Any can explain how it will be answer D?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers