Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 6 (Q.No. 4)
4.
The shear stress at the centre of a circular shaft under torsion is
Discussion:
6 comments Page 1 of 1.
Robjn said:
6 years ago
T/j = shear stress/radius.
So, the shear stress is directly proportional to radius so the answer is correct.
So, the shear stress is directly proportional to radius so the answer is correct.
Gautam shubhashish said:
7 years ago
Actually there are 2 types of shear stress. . Shear stress due to shear force and second one is shear stress due to torsion. . In the first one, shear stress is maximum at the centre and it is zero in the second case.
(1)
Sourabh Patil said:
8 years ago
Here we consider only torsion The shear stress is directly proportional to the shaft radius (in torsion). (tau/r).
So in the middle, the are = 0, so the shear stress is also zero.
In shaft subjected to only shear stress at centre shear stress is maximum (tau = SAY/bi).
So in the middle, the are = 0, so the shear stress is also zero.
In shaft subjected to only shear stress at centre shear stress is maximum (tau = SAY/bi).
Vanraj Gajarotar said:
8 years ago
Shear stress is maximum at the center of the circular shaft. Because of it inversely proportional to radius according to the equation.
Newton said:
8 years ago
The shear stress is directly proportional to the shaft radius (in torsion).
So in the middle, the radius is zero, so the shear stress is also zero.
So in the middle, the radius is zero, so the shear stress is also zero.
Keerthana said:
10 years ago
Shear stress is maximum at the center of circular shaft.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers