Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 41)
41.
The maximum deflection of a fixed beam of length l carrying a central point load W is
Discussion:
5 comments Page 1 of 1.
Abbas said:
2 months ago
Yes, it's fixed not simply supported.
Mahesh said:
1 year ago
Answer is A.
For a fixed beam of length ll carrying a central point load WW, the maximum deflection (\delta_{max}δ
max) can be calculated using the following formula:
\delta_{max} = \frac{{W l^3}}{{48 E I}}δ.
max = Wl^3/48EI.
Where:
WW = Load applied at the centre.
ll = Length of the beam.
EE = Young's modulus (modulus of elasticity) of the beam material.
II = Moment of inertia of the beam's cross-sectional area.
For a fixed beam of length ll carrying a central point load WW, the maximum deflection (\delta_{max}δ
max) can be calculated using the following formula:
\delta_{max} = \frac{{W l^3}}{{48 E I}}δ.
max = Wl^3/48EI.
Where:
WW = Load applied at the centre.
ll = Length of the beam.
EE = Young's modulus (modulus of elasticity) of the beam material.
II = Moment of inertia of the beam's cross-sectional area.
Manoj tikadar said:
5 years ago
I think Option A is the correct answer.
Dinu said:
5 years ago
Fixed at both ends so the answer max Deflection = wl3/192EI is correct.
Chaitanya said:
6 years ago
I think Option A is correct.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers