Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is 
.
. Discussion:
67 comments Page 6 of 7.
Kokre dnyanoa said:
1 decade ago
Apply McCauley's method. They can easily solve this concept.
Tushar Jha said:
1 decade ago
Answer should be A. Since the deflection at any point on a SSB is given by the same formula. It can be verified for maximum deflection at center for a SSB.
Pitla prakash said:
1 decade ago
Maximum deflection occurs at center.
Rajesh said:
1 decade ago
Ans: A.
Maximum deflection at the center = (wl^3)/(192EI) if a = b = l/2.
Maximum deflection at the center = (wl^3)/(192EI) if a = b = l/2.
Gaurav said:
1 decade ago
Answer should be A.
Max.deflection = WL^3/48EI.
Put a = b = L/2.
Max.deflection = WL^3/48EI.
Put a = b = L/2.
PRADEEP VERMA said:
1 decade ago
MAX.DEFLECTION = Wab^3/3EI(a+b) = Wab^3/3EIL.
SUJAY LONDHE said:
1 decade ago
Given value is Deflection at Point C.
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).
Ravinder kumar said:
1 decade ago
In simply supported beam max.defletion is at center of beam.
Hanu said:
1 decade ago
In simply supported beam max deflection occurs at center of the load applied.
Jayanaidu said:
1 decade ago
Above question is satisfying the equation when a=l/2, b=l/2 in the w*a^2*b^2/48EI.
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