Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is .
True
False
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
67 comments Page 2 of 7.

Gautam shubhashish said:   8 years ago
In unsymmetrically loaded ssb, the deflection is going to be maximum in the REGION between applied load and mid-span.

Saiteja said:   2 years ago
According to the figure, the answer is correct but according to c's position the right answer is:- (Wa^2c^3)/384EI.
(1)

Prasad said:   1 decade ago
When simply supported beam deflection is wl3/48EI AND IS satisfy above equation if we take a and b equal to L/2.

Sumit Dharmarao said:   1 decade ago
Whatever mentioned above is deflection at C & Max. Deflection = ((wa(l^2-a^2)^1.5))/9*3^(1/2)*EIl)).

Rajkotha said:   7 years ago
In simply supported beams deflection =Wl^3/48EI.

In simpy supported with UDL deflection =5Wl^4/384EI.

Raushan said:   9 years ago
@All.

Check the unit of the answer. Here that is not in meter but meter^2.

So, FALSE(B).

SUJAY LONDHE said:   1 decade ago
Given value is Deflection at Point C.
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).

MD NASEERUDDIN said:   7 years ago
According to Maculay's method when point load act on eccentric then the answer is correct.

Dwaipayan said:   7 years ago
The expression given is True, put, a=b=l/2, and you will get the expression, Wl^3/48EI.
(1)

Sagar k.r said:   10 years ago
The deflection at C is true, since b & a .

Therefore, maximum deflection occurs in CB.


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