Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 11)
11.
For a beam, as shown in the below figure, the maximum deflection is 
.
. Discussion:
68 comments Page 2 of 7.
Sanchez said:
1 decade ago
By McCauley's method.
Max deflection = wba3/3EI as max deflection occur under loading i.e. - x=a from left support.
Max deflection = wba3/3EI as max deflection occur under loading i.e. - x=a from left support.
Saiteja said:
3 years ago
According to the figure, the answer is correct but according to c's position the right answer is:- (Wa^2c^3)/384EI.
(1)
Prasad said:
1 decade ago
When simply supported beam deflection is wl3/48EI AND IS satisfy above equation if we take a and b equal to L/2.
Sumit Dharmarao said:
1 decade ago
Whatever mentioned above is deflection at C & Max. Deflection = ((wa(l^2-a^2)^1.5))/9*3^(1/2)*EIl)).
Rajkotha said:
7 years ago
In simply supported beams deflection =Wl^3/48EI.
In simpy supported with UDL deflection =5Wl^4/384EI.
In simpy supported with UDL deflection =5Wl^4/384EI.
Raushan said:
10 years ago
@All.
Check the unit of the answer. Here that is not in meter but meter^2.
So, FALSE(B).
Check the unit of the answer. Here that is not in meter but meter^2.
So, FALSE(B).
SUJAY LONDHE said:
1 decade ago
Given value is Deflection at Point C.
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).
Max.Deflection = Wa*((l^2-a^2)^3/2)/(9*1.732*E*I*L).
MD NASEERUDDIN said:
8 years ago
According to Maculay's method when point load act on eccentric then the answer is correct.
Dwaipayan said:
8 years ago
The expression given is True, put, a=b=l/2, and you will get the expression, Wl^3/48EI.
(1)
Sagar k.r said:
1 decade ago
The deflection at C is true, since b & a .
Therefore, maximum deflection occurs in CB.
Therefore, maximum deflection occurs in CB.
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