Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 9 (Q.No. 12)
12.
The maximum shear stress developed in a beam of circular section is __________ the average shear stress.
Discussion:
4 comments Page 1 of 1.
Uvais Akhtar said:
6 years ago
The maximum shear stress in a circular section 4/3.
Rajkotha said:
6 years ago
The maximum shear stress in the circular section -4/3.
The maximum shear stress in rectangular -3/2.
The maximum shear stress in rectangular -3/2.
HAMED said:
9 years ago
Max shear= VQ/Ib.
Q = (Pi * R^2/2) * (4R/3Pi).
b = 2R.
I = Pi * R^4/4.
THANK YOU.
Q = (Pi * R^2/2) * (4R/3Pi).
b = 2R.
I = Pi * R^4/4.
THANK YOU.
Venkat said:
9 years ago
Can anyone explain this?
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