Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 39)
39.
If the depth is kept constant for a beam of uniform strength, then its width will vary in proportional to (where M = Bending moment)
M
M
M2
M3
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

Anand said:   5 years ago
It's √M if width has been kept constant and depth varies.

Because M/I = stress/y and y is d/2.

Now I= bd^3/12 solving u get d proportional to √M.

But in this question, depth is kept constant and the I will be same as above so b gets proportional to M.
(1)

Navaneeth said:   5 years ago
A beam of uniform strength means the load is uniform (depending on the area the load is applied i.e, if the area is minimum the load applied is minimum and if the area is maximum the load applied is maximum)

The main aim of a beam of uniform strength is to reduce cost and make economical beams.

Width varies directly proportional to M.

Uvl width =wx/L.
Udl width=wL.
Point load/concentrated load=w.

AMOL said:   7 years ago
M= Ru * bd2.

Therefore,
M is directly proportional to Breadth.

Sozharajan said:   8 years ago
Why not √M?

Explain the answer.

Venkatesh K said:   1 decade ago
Bending moment M = (B*D^3)/12.

SO depth constant so M is directly proportional to Breadth(B).

Arjun said:   1 decade ago
M/I = sigma/Y.

I = (bd^3)/12.

Y = d/2.
Where,
b = width.
d = depth.

So b proportional to M.

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