Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 8 (Q.No. 7)
7.
The strain energy stored in a body, when suddenly loaded, is __________ the strain energy stored when same load is applied gradually.
Discussion:
21 comments Page 1 of 3.
Gaurav said:
1 decade ago
strain energy is directly proportional to stress^2.
Anil kapkoti said:
9 years ago
The right answer is twice.
Harikesh D said:
8 years ago
According to me, the correct answer is B.
Shahrukh said:
8 years ago
What is the formula for this?
Sweta said:
8 years ago
The given answer is correct.
With gradual loading, it is half the stress produce than without gradual.
With sudden loading, it is twice the stress produce than without sudden.
Hence, strain energy for sudden loading will be 1/4th of gradual loading.
With gradual loading, it is half the stress produce than without gradual.
With sudden loading, it is twice the stress produce than without sudden.
Hence, strain energy for sudden loading will be 1/4th of gradual loading.
Suranjan said:
8 years ago
Strain energy = .5 * W * dL = (.5*W^2*L)/AE.
Now, the load is twice wen it is sudden w.r.t gradually applied.
Strain energy for sudden applied load = [.5 * (2W)^2 * L]/AE = 4[.5 * W^2 * L]/AE.
Now, the load is twice wen it is sudden w.r.t gradually applied.
Strain energy for sudden applied load = [.5 * (2W)^2 * L]/AE = 4[.5 * W^2 * L]/AE.
Ranajay said:
8 years ago
As stress is 2 times in case of sudden loading the strain energy.
U=(sigma^2/2E)*V,
And sigma = 2(p/A),
Therefore strain energy in case of sudden loading is 4 times than in the case of gradual loading.
U=(sigma^2/2E)*V,
And sigma = 2(p/A),
Therefore strain energy in case of sudden loading is 4 times than in the case of gradual loading.
Anil said:
8 years ago
Gradually applied load is given as σ = (F/A) ------ (F is the gradually applied load)
Here, work done is given as (F δL) / 2 and strain energy stored = (σ2 / 2E) AL
Work done is equal to the strain energy stored.
(F δL) / 2 = (σ2 / 2E) AL
Therefore, σ = (F/A) ----------- (1)
- Suddenly applied load is given as σ = (2F/A), here work done = (F δL)
(F δL) = (σ2 / 2E) AL
Therefore, σ= (2F/A) ------------- (2)
From (1) and (2), it can be concluded that,
Hence, suddenly applied load is twice the gradually applied load.
Here, work done is given as (F δL) / 2 and strain energy stored = (σ2 / 2E) AL
Work done is equal to the strain energy stored.
(F δL) / 2 = (σ2 / 2E) AL
Therefore, σ = (F/A) ----------- (1)
- Suddenly applied load is given as σ = (2F/A), here work done = (F δL)
(F δL) = (σ2 / 2E) AL
Therefore, σ= (2F/A) ------------- (2)
From (1) and (2), it can be concluded that,
Hence, suddenly applied load is twice the gradually applied load.
Tejas said:
8 years ago
Answer is twice.
CPv said:
8 years ago
Stress : - twice.
Strain energy :- four times.
Strain energy :- four times.
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