Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 50)
50.
In Mohr's circle, the centre of circle from Y-axis is taken as
Discussion:
13 comments Page 1 of 2.
BIPLAB said:
9 years ago
The correct answer is A.
Shisi said:
9 years ago
A is the answer. I too agree.
Bharat khot said:
8 years ago
I too think A is the correct answer.
Shruti said:
8 years ago
Option B is correct.
Option A is nothing but the radius of mohr's circle or Max shear stress.
Option A is nothing but the radius of mohr's circle or Max shear stress.
DHARMVIR said:
8 years ago
If principal stresses are alike than answer A.
If unlike than answer B.
If unlike than answer B.
Keshav said:
8 years ago
Answer is right but it must be from X axis.
Sumit kumar said:
7 years ago
Option B is absolutely correct. I agree.
Sumit kumar said:
7 years ago
σ X + ( σy -σX)/2= (X+y)/2.
From y-axis.
From y-axis.
Rajib said:
7 years ago
Option A is correct. I too agree.
Ankita said:
6 years ago
The distance between Y-axis (vertical line) and the centre of the circle is measured along X-axis(horizontal line), which is σ avg = (σX+σY)/2.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers