Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 4)
4.
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum shear stress will be
Discussion:
4 comments Page 1 of 1.
Akash said:
7 years ago
Answer is 500. I agree with the given answer.
Deepu said:
7 years ago
Here, (√(1200-600)^2/2+400^2)^2 gives 500.
25635 said:
1 decade ago
(t)max when d(ts)/d0 = 0.
tan20 = (sigma)x-(sigma)y/2(ts).
2thita = 36.86.
And we know (ts)=-1/2((sigma)x-(sigma)y)sin20+(txy)cos20.
After putting the values we get 143.041.
Please tell me whether it is correct or not?
tan20 = (sigma)x-(sigma)y/2(ts).
2thita = 36.86.
And we know (ts)=-1/2((sigma)x-(sigma)y)sin20+(txy)cos20.
After putting the values we get 143.041.
Please tell me whether it is correct or not?
D. PRASAD BABU, RKV said:
1 decade ago
(t)max = 1/2[(sigma1-sigma2)^2+4T^2]^1/2.
= 500 MPa.
= 500 MPa.
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