Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
Discussion:
57 comments Page 4 of 6.
Mithlesh said:
10 years ago
Its due to normal stress formula.
Pradeep yadav said:
10 years ago
@Suresh you have any formula for normal stress in this manner.
Nabin said:
1 decade ago
LET
T.S1=1200 and T. S2=600 and S.S=400 normal stress = T.S1+T.S2-S.S.
Then 1200+600-400 = 1400. So maximum normal stress = 1400 Mpa.
T.S1=1200 and T. S2=600 and S.S=400 normal stress = T.S1+T.S2-S.S.
Then 1200+600-400 = 1400. So maximum normal stress = 1400 Mpa.
Shahrukh ansari said:
1 decade ago
Max. normal stress is equal to max. principal stress.
Mona said:
1 decade ago
I need the solution urgently need. Can you please solve again?
Harish said:
1 decade ago
Can you solve this sum again clearly?
Heny man said:
1 decade ago
Can you proof it again clearly?
Suresh said:
1 decade ago
The maximum stress = x+y-z.
= 1400+600-200.
= 1400+600-200.
Saravanakumar said:
1 decade ago
Normal stress are the average stress in X and Y direction.
At particular plane that means angle of rotation the Normal stress will be maximum that plane/stress is called principle plane/stress.
At particular plane that means angle of rotation the Normal stress will be maximum that plane/stress is called principle plane/stress.
Vaibhav said:
1 decade ago
Max normal stress = Principle stress.
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