Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 7)
7.
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
Discussion:
57 comments Page 3 of 6.
L3FA said:
9 years ago
Thanks for the given explanations.
Rakesh patra said:
8 years ago
Principle stress are maximum or minimum normal stress which may be developed on a loaded body.
Ram prasad said:
8 years ago
Thanks for the given explanation.
Yajat Sharma said:
10 years ago
Maximum. normal stress = T.S - S.S.
= T.S1 + T.S2 - S.S.
= 1200 + 600 - 400 .
= 1400 answer.
= T.S1 + T.S2 - S.S.
= 1200 + 600 - 400 .
= 1400 answer.
Hareshkumar said:
8 years ago
The resultant tensile stress is (1200+600)/2 =900 MPA shear stress =400 Mpa using maximum normal stress theory 1/2(900+ 900^2+4 * 400^2) = 1400Mpa.
Afrooj said:
8 years ago
Thanks for all for the explanation.
Kaushal roy said:
7 years ago
Two different stress act on a member design should be based on max principal stress so here we find max principal stress.
Yugal Chaudhari said:
6 years ago
Use @Kamal talukdar formula. It is correct.
Dadi Lavanya lahari said:
12 months ago
Thank you for explaining the answer @Sagarbankar.
Sumit said:
1 decade ago
Principal Stress: Maximum and minimum normal stress possible for a specific point on a structural element.
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