Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 8 (Q.No. 31)
31.
A body is subjected to a direct tensile stress of 300 MPa in one plane accompanied by a simple shear stress of 200 MPa. The maximum normal stress will be
Discussion:
12 comments Page 2 of 2.
AMANDEEP Singh mattu said:
4 years ago
Formula = 300 /2 +1/2 under root (300)^2+4(200)^2 = 500.
300/2 = 150, 1/2 = 0.5,
500*.5 = 250 + 150 = 400 max normal stress.
300/2 = 150, 1/2 = 0.5,
500*.5 = 250 + 150 = 400 max normal stress.
Rashid Khan Kakar said:
4 years ago
150+1/2* √(300^2+4*200^2) = 400.
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