Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 7 (Q.No. 4)
4.
A body is subjected to a direct tensile stress (σ) in one plane. The shear stress is maximum at a section inclined at __________ to the normal of the section.
Discussion:
1 comments Page 1 of 1.
Ashok kumar said:
10 years ago
Shear stress = Direct stress/2σ-sin2@. Where @ is angle from x-axis. It is max when sin2 @ =1.
So @ = 45° or 135°.
So @ = 45° or 135°.
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