Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 17)
17.
The maximum diameter of the hole that can be punched from a plate of maximum shear stress 1/4th of its maximum crushing stress of punch, is equal to (where t = Thickness of the plate)
t
2t
4t
8t
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
65 comments Page 6 of 7.

Sarath t r said:   9 years ago
Anybody. please help me. Actually what is the equation of crushing stress and how it came?

Praveen said:   9 years ago
@Sarath.

Crushing stress = f\crushing area.
Crushing area = pi * d * d/4.

Mukesh said:   9 years ago
1/4 s.s = c.s
1/4 * F/pi d t = F/pi d d.
d = 4t.

Ajitesh said:   9 years ago
σs = (1/4)σc.
F/(Φ d.t) = F/((Φ/4).d^2.t).
d = t.

NITESH BORKAR said:   9 years ago
The equation will be:

(Pi/4 * d^2) * Crushing strength,

= Pi * d * t * Shear strength (or crushing strength * 2).

Which comes out to be t only.

Deepak said:   9 years ago
S.S = ( 1/4) * C.S.
F/Pi dt = (1/4) * (4F/pi * d^2).
Thus, d = t.

Indrajeet said:   9 years ago
Option A is the correct answer.

Crushing stress = 4 * Load(P)/φ * D * D.

Shear stress = Load(P)/φ * D * t.

Since Crushing stress = 4 * Shear stress.

After resolve, We get, D = t.

So option A is right.

Sridevi said:   9 years ago
Yes, agree that d = t.

Ananth said:   9 years ago
Shear stress = Load(P)/φ * D * t.
φ * D * t = ?

(area= L*T or (φ * D2)/4).

Koribilli hemanth said:   9 years ago
Answer was wrong.

The right answer is T = D.
Shear force = pi * D * T * shear stress.
Crushing force = (pi/4) * D^2 * crushing stress.

The condition is that "crushing stress = 4 * shear stress " at equilibrium condition " shear force = crushing force"

pi * D * T * shear stress = (pi/4) * D^2 * crushing stress.

By canceling the terms finally we will get D = T.


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