Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 3)
3.
A bar of length L metres extends by l mm under a tensile force of P. The strain produced in the bar is
Discussion:
6 comments Page 1 of 1.
Trkant said:
7 years ago
0.001l /L because l will be in the meter.
SJP said:
7 years ago
l in mm.
L in meters.
By MKS system, mm to be converted into the meter. Hence, strain= (l/1000L)= 0.001 l/L.
L in meters.
By MKS system, mm to be converted into the meter. Hence, strain= (l/1000L)= 0.001 l/L.
Pritish said:
1 decade ago
Strain = Change in length/original length.
= dl/l.
= 1mm/1m.
0.001/1.
= dl/l.
= 1mm/1m.
0.001/1.
(1)
SHASHANK said:
1 decade ago
STRAIN = CHANGE IN LENGTH / ORIGINAL LENGTH.
STRAIN = l (mm)/L (mm).
STRAIN = 10^-3 l / L.
STRAIN = 0.001 l/L.
STRAIN = l (mm)/L (mm).
STRAIN = 10^-3 l / L.
STRAIN = 0.001 l/L.
Vijay said:
1 decade ago
Strain produced is tensile strain.
Strain = change in length/original length.
Strain = change in length/original length.
Subbu said:
1 decade ago
Because strain = extension/length before load application.
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