Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 25)
25.
Two bars of different materials and same size are subjected to the same tensile force. If the bars have unit elongation in the ratio of 2:5, then the ratio of modulus of elasticity of the two materials will be
Discussion:
12 comments Page 2 of 2.
Vipin sainath said:
5 years ago
We know that,
E= stress/strain,
Strain = change in length / original length => 2/5 / 1 ( assume original length is equal to 1).
So, Strain = 2/5 then E= stress / (2/5) ... finally, we get,
E = 1 / (2/5)...... as you can see E is inversely proportional to strain ( change in length),
So, E = 5/2 or 5:2.
E= stress/strain,
Strain = change in length / original length => 2/5 / 1 ( assume original length is equal to 1).
So, Strain = 2/5 then E= stress / (2/5) ... finally, we get,
E = 1 / (2/5)...... as you can see E is inversely proportional to strain ( change in length),
So, E = 5/2 or 5:2.
Hari said:
4 years ago
It is inversely proportional.
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