Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 25)
25.
Two bars of different materials and same size are subjected to the same tensile force. If the bars have unit elongation in the ratio of 2:5, then the ratio of modulus of elasticity of the two materials will be
Discussion:
12 comments Page 1 of 2.
Vipin sainath said:
5 years ago
We know that,
E= stress/strain,
Strain = change in length / original length => 2/5 / 1 ( assume original length is equal to 1).
So, Strain = 2/5 then E= stress / (2/5) ... finally, we get,
E = 1 / (2/5)...... as you can see E is inversely proportional to strain ( change in length),
So, E = 5/2 or 5:2.
E= stress/strain,
Strain = change in length / original length => 2/5 / 1 ( assume original length is equal to 1).
So, Strain = 2/5 then E= stress / (2/5) ... finally, we get,
E = 1 / (2/5)...... as you can see E is inversely proportional to strain ( change in length),
So, E = 5/2 or 5:2.
Sourava said:
6 years ago
Elongation, e1 = PL/AE1 (for 1st material).
or, E1 = PL/Ae1.
e2 = PL/AE2 (for 2nd material).
or, E2 = PL/Ae2.
Now, E1/E2 = (PL/Ae1)/(PL/Ae2).
= e2/e1.
= 1/(e1/e2).
Hence, the ratio of modulus of elasticity of the two material is 5:2.
or, E1 = PL/Ae1.
e2 = PL/AE2 (for 2nd material).
or, E2 = PL/Ae2.
Now, E1/E2 = (PL/Ae1)/(PL/Ae2).
= e2/e1.
= 1/(e1/e2).
Hence, the ratio of modulus of elasticity of the two material is 5:2.
AMAL said:
10 years ago
e(strain) = delta l(change in length)/original length.
Strain = stress/E.
Strain = Change in length (elongation) is inversely proportional to E.
That is 5:2.
Strain = stress/E.
Strain = Change in length (elongation) is inversely proportional to E.
That is 5:2.
(1)
Rushi said:
9 years ago
Delta L = PL/AE.
Let, delta L a/deltaLb = 2/5.
(PL/AE) a* (AE/PL) = 2/5.
Eb/Ea = 2/5.
Ea/Eb = 5/2.
Let, delta L a/deltaLb = 2/5.
(PL/AE) a* (AE/PL) = 2/5.
Eb/Ea = 2/5.
Ea/Eb = 5/2.
Princess said:
7 years ago
δL is inversely proportional to E.
So δL is 2/5 and hence E becomes 1/ (2/5) = 5/2.
So δL is 2/5 and hence E becomes 1/ (2/5) = 5/2.
Nauman Akram said:
5 years ago
&l=pl/AE.
E1=pl/2A.
E2=pl/5A.
E1/E2 =pl/2A/pl/5A.
E1/E2= 5/2.
E1/E2 = 5: 2.
E1=pl/2A.
E2=pl/5A.
E1/E2 =pl/2A/pl/5A.
E1/E2= 5/2.
E1/E2 = 5: 2.
(3)
ATUL said:
9 years ago
E1 = E2.
PL/A $L1= PL/A $L2
1/$L1= 1/ $L2
1/2= 1/5
THEREFORE 5/2.
PL/A $L1= PL/A $L2
1/$L1= 1/ $L2
1/2= 1/5
THEREFORE 5/2.
Abhay said:
7 years ago
E1=1/2.
E2=1/5.
δ = E1/E2,
= 5/2,
OR 5:2.
E2=1/5.
δ = E1/E2,
= 5/2,
OR 5:2.
Sri said:
9 years ago
But they are comparing to two bars na.
Swap said:
9 years ago
Yes, right. How is that possible?
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