Mechanical Engineering - Steam Nozzles and Turbines - Discussion
Discussion Forum : Steam Nozzles and Turbines - Section 1 (Q.No. 35)
35.
In a De-Laval nozzle expanding superheated steam from 10 bar to 0.1 bar, the pressure at the minimum cross-section (i. e. pressure at throat, p2) will be
Discussion:
8 comments Page 1 of 1.
Shantanu Pal said:
1 decade ago
Cause p2/p1 = 0.546 as the steam is initially super heated and n = 1.3. Now, p1 = 10 bar. So the pressure at throat p2 will be 0.546*10 = 5.46 bar.
Felix said:
10 years ago
Pressure ratio (p2/p1 = 0.546), while p1 = 10 bar, p2 = 10x0.546, p2 = 5.46.
Daka Hitesh said:
9 years ago
Pressure Ratio:
For Gas : 0.462.
For Wet : 0.582.
For Saturated : 0.577.
For Super Heated :0.546.
For Gas : 0.462.
For Wet : 0.582.
For Saturated : 0.577.
For Super Heated :0.546.
(1)
Anil said:
8 years ago
You are Exactly Correct @Daka Hitesh.
(1)
Kunal said:
8 years ago
Critical pressure ratio.
Pc/P1 = (2/n+1)^(n/n-1),
P1 = 10,
n = 1.3 for supersaturated steam.
Pc/P1 = (2/n+1)^(n/n-1),
P1 = 10,
n = 1.3 for supersaturated steam.
Navyaa said:
7 years ago
Thanks all for explaining it.
Siddu said:
6 years ago
P2/p1 = 0.546 for super saturated steam
And 0.578 for dry saturated steam,
And 0.582 for the wet st.eam,
In problem p1 is given as 10,
Then p2= 0.546 * 10 because super saturated steam p2 = 5.46.
And 0.578 for dry saturated steam,
And 0.582 for the wet st.eam,
In problem p1 is given as 10,
Then p2= 0.546 * 10 because super saturated steam p2 = 5.46.
(2)
Mayank sonagara said:
4 years ago
@All.
Thank you so much for the explanation.
Thank you so much for the explanation.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers