Mechanical Engineering - Steam Boilers and Engines - Discussion
Discussion Forum : Steam Boilers and Engines - Section 4 (Q.No. 30)
30.
A throttle governed steam engine develops 15 kW with 280 kg per hour of steam and 35 kW with 520 kg per hour of steam. The steam consumption in kg per hour when developing 20 kW will be nearly
Discussion:
4 comments Page 1 of 1.
AMAL said:
10 years ago
Using interpolation:
15---->280.
20----->x.
35----->520.
Where x is the steam consumption at 20 kw.
(20-15)/(x-280) = (35-15)/(520-280).
5/20 = (x-280)/(240).
x = 280+60 = 340.
15---->280.
20----->x.
35----->520.
Where x is the steam consumption at 20 kw.
(20-15)/(x-280) = (35-15)/(520-280).
5/20 = (x-280)/(240).
x = 280+60 = 340.
(1)
Bharat said:
1 decade ago
y=mx+c;
Here y = Rate of mass of steam;
m = ip;
So 280 = 15a+b;
520 = 35a+b;
Solving a=12; b=100.
Here y = Rate of mass of steam;
m = ip;
So 280 = 15a+b;
520 = 35a+b;
Solving a=12; b=100.
Abe said:
8 years ago
Option A and B which are less than 280 eliminated. 280 cannot be the answer because it produces 15kw. So answer should be D.
Keyur said:
8 years ago
Good explanation @ Bharat @Amal.
Good logic @ abe.
Good logic @ abe.
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