Mechanical Engineering - Production Engineering - Discussion
Discussion Forum : Production Engineering - Section 6 (Q.No. 21)
21.
It is required to cut screw threads of 2 mm pitch on a lathe. The lead screw has a pitch of 6 mm. If the spindle speed is 60 r.p.m., then the speed of lead screw will be
Discussion:
10 comments Page 1 of 1.
Ganeshr said:
5 years ago
@Tej.
Correct formula. Thanks.
Correct formula. Thanks.
Krish said:
5 years ago
Thank you all.
Tej said:
5 years ago
n1P1N1=n2P2N2.
Where
n:no Of starts.
P:pitch.
N:RPM.
1: Workpiece or spindle.
2: Leadscrew.
Where
n:no Of starts.
P:pitch.
N:RPM.
1: Workpiece or spindle.
2: Leadscrew.
(1)
Venkatraman B said:
5 years ago
v = s/t.
Here time t is constant.
V1/S1 = V2/S2.
V2=60*2/6=20 rpm.
Here time t is constant.
V1/S1 = V2/S2.
V2=60*2/6=20 rpm.
Suresh said:
6 years ago
Thank you for explaining the answer.
SAMEER ansari said:
6 years ago
Thank you @Vijay.
Abdul said:
10 years ago
N1*pitch1*dia1/60 = N2*pitch2*dia2/60.
N2 = 60*2/60 = 20 r.p.m.
N2 = 60*2/60 = 20 r.p.m.
Vijay said:
1 decade ago
Speed of lead screw=Spindle speed*Pitch/P of lead screw.
= 60*2/6 = 20.
= 60*2/6 = 20.
Shashi said:
1 decade ago
Can anyone explain the process please?
Nitesh mande said:
1 decade ago
Please provide solution.
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