Mechanical Engineering - Production Engineering - Discussion
Discussion Forum : Production Engineering - Section 1 (Q.No. 39)
39.
In the relation VTn = C, the value of n for carbide tools is
Discussion:
10 comments Page 1 of 1.
Bhavik said:
8 years ago
High-speed steels 0.08-0.2.
Cast alloys 0.1-0.15.
Carbides 0.2-0.5.
Coated carbides 0.4-0.6.
Ceramics 0.5-0.7.
Ref: MANUFACTURING ENGINEERING AND TECHNOLOGY SIXTH EDITION by Serope Kalpakjian.
Cast alloys 0.1-0.15.
Carbides 0.2-0.5.
Coated carbides 0.4-0.6.
Ceramics 0.5-0.7.
Ref: MANUFACTURING ENGINEERING AND TECHNOLOGY SIXTH EDITION by Serope Kalpakjian.
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All said:
2 years ago
Values of Exponent n.
High-Speed steels 0.08 – 0.20.
Cast Alloys 0.10 – 0.15,
Carbides 0.20 – 0.50,
Coated carbides 0.40 – 0.60,
Ceramics 0.50 – 0.70.
High-Speed steels 0.08 – 0.20.
Cast Alloys 0.10 – 0.15,
Carbides 0.20 – 0.50,
Coated carbides 0.40 – 0.60,
Ceramics 0.50 – 0.70.
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Kareem said:
1 decade ago
For h.c steels n = 0.05-0.1.
n = 0.1-.2 for h.s.s.
n = 0.2-0.4 for carbides.
n = 0.4-0.6 for ceramics.
n = 0.7-0.9 for diamonds.
n = 0.1-.2 for h.s.s.
n = 0.2-0.4 for carbides.
n = 0.4-0.6 for ceramics.
n = 0.7-0.9 for diamonds.
Gujarat kumar said:
6 years ago
Taylor's tool life equation.
VTn= c.
V= velocity a tool.
T= tool life.
C= machining constant.
N= tool life in the exponent.
VTn= c.
V= velocity a tool.
T= tool life.
C= machining constant.
N= tool life in the exponent.
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Sunny kumar jha said:
1 decade ago
n = 0.2-0.4 for carbides. Its your suggestion but also n = 0.20 to 0.25 is given for that question is correct. How?
Neeraj said:
9 years ago
0.08-0.2- HSS.
0.1-0.15- Cast iron.
0.2-0.4- Carbide.
0.5-0.7- Ceremic.
0.1-0.15- Cast iron.
0.2-0.4- Carbide.
0.5-0.7- Ceremic.
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Divesh said:
9 years ago
In my opinion 0.25 - 0.40 is correct answer.
Vinay BEL said:
5 years ago
[C]. 0.25 to 0.40 is the correct answer.
Abhishek said:
1 decade ago
Why not 0.25 to 0.40 is correct?
Utkarsh said:
7 years ago
Why not .25 to .40?
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