Mechanical Engineering - Machine Design - Discussion


The velocity factor for ordinary cut gears operating at velocities upto 12.5 m/s is equal to


Answer: Option B


No answer description available for this question.

Amarjit said: (May 15, 2016)  
When two gears are running at the high speed it is found that the load experienced by those gears is increased. In an attempt to quantify this, experiments were carried out where gears were tangentially loaded to failure under zero velocity and then loaded to failure at a specific pitching velocity (velocity along the line of action).

The ratio of the static load at the failure to the dynamic load at failure was taken as the Velocity factor (Kv). This means that an identical gear pair running at this speed would have a dynamic load equal to Kv times the static tangential load.

Sneha said: (May 21, 2018)  
D is the correct option.

Rashmi said: (Jun 26, 2018)  
What is the velocity factor for carefully cut gears operating at velocities up to 760 m/min? Please explain.

Ankita said: (Aug 20, 2018)  
As per my knowledge, wd v<20m/s follow the formula 6/(6+v).

Rohit said: (Oct 18, 2018)  
The right answer is (C).

Rajjo said: (Dec 23, 2018)  
How @Rohit?

Please tell me.

Rohit said: (Jan 9, 2019)  
Yes, D is correct. I also agree.

Mshij said: (Mar 26, 2019)  
Isn't option D is for carefully cut gear?

Sid said: (Apr 16, 2019)  
For 12.5 it is 3/3+v.
For 20m/s it is 6/6+v.

Gautham said: (May 23, 2019)  
In case of ordinary cut gears B becomes correct.

In case of carefully cut gears C becomes correct.

Dalidhananjay said: (Jul 24, 2021)  
As per my knowledge, wd v<20m/s follow the formula 6/(6+v).

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