Mechanical Engineering - Machine Design - Discussion
Discussion Forum : Machine Design - Section 2 (Q.No. 40)
40.
When spring index increases, the value of Wahl's stress factor
Discussion:
10 comments Page 1 of 1.
Ranjan said:
6 years ago
It should decrease exponentially.
(2)
Dhaval Chaudhary said:
7 years ago
Option D is the right answer. I agree.
Dhaval said:
8 years ago
Yeah, it should decrease.
(1)
Peddiraju said:
8 years ago
K = 4C-1/4C-4+0.615/C as per formula decrease exponentially.
(3)
Uzair Malik said:
8 years ago
Yes, Wahl stress factor 'K' increases exponentially with the decrease in spring index 'C'.
Well said @Dakahitesh.
Well said @Dakahitesh.
Dakahitesh said:
9 years ago
C --> K Wahl's Factor
2 --> 2.0575
3 --> 1.5800
4 --> 1.4038
5 --> 1.3105
6 --> 1.2525
7 --> 1.2129
8 --> 1.1840
9 --> 1.1621
10 --> 1.1448
11 --> 1.1309
12 --> 1.1194
13 --> 1.1098
14 --> 1.1016
15 --> 1.0946
16 --> 1.0884
17 --> 1.0831
18 --> 1.0783
19 --> 1.0740
20 --> 1.0702
21 --> 1.0668
As Spring index decrease then value of Wahl's stress factor increase exponentially.
2 --> 2.0575
3 --> 1.5800
4 --> 1.4038
5 --> 1.3105
6 --> 1.2525
7 --> 1.2129
8 --> 1.1840
9 --> 1.1621
10 --> 1.1448
11 --> 1.1309
12 --> 1.1194
13 --> 1.1098
14 --> 1.1016
15 --> 1.0946
16 --> 1.0884
17 --> 1.0831
18 --> 1.0783
19 --> 1.0740
20 --> 1.0702
21 --> 1.0668
As Spring index decrease then value of Wahl's stress factor increase exponentially.
(1)
Prakash said:
9 years ago
When Spring index increase, the Wahl's stress factor decrease exponentially. But curvature stress increase with increase spring index.
Gaurav said:
9 years ago
@Vivek and Chintan are right.
Chintan patel said:
10 years ago
Spring index decrease then value of Wahl's stress factor increase exponentially.
Vivek said:
1 decade ago
As spring index increases, k decreases exponentially.
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