IndiaBIX

Mechanical Engineering - Machine Design - Discussion

Discussion Forum : Machine Design - Section 9 (Q.No. 14)
Machine Design
14.
When a belt drive is transmitting maximum power,
effective tension is equal to centrifugal tension
effective tension is half of centrifugal tension
driving tension on slack side is equal to centrifugal tension
driving tension on tight side is twice the centrifugal tension
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
5 comments Page 1 of 1.
L Rajendra said:   4 years ago
Good explanation. Thanks.
Satish pandey said:   7 years ago
Tmax=T1+Tc.
And Tmax=3Tc (from max power transmission cond).
So, 3Tc=T1+T.
Now, T1=2Tc.
ATC said:   8 years ago
Maximum Tension is on tight side : Tmax= 3Tc
So the maximum tension on driving side = T1+Tc.
ie 3Tc = T1+TCS.
T1= 2Tc.
(1)
Dinesh said:   8 years ago
Here, T max = 3Tc.
SANDIP said:   9 years ago
Tmax = T1 + Tc,
AND Tmax = 3Tc,
=> T1 = 2Tc.
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers