Mechanical Engineering - Machine Design - Discussion
Discussion Forum : Machine Design - Section 1 (Q.No. 4)
4.
The number of rivets in shear shall be equal to the number of rivets in crushing.
Discussion:
9 comments Page 1 of 1.
Nishant said:
6 years ago
option A is saying correct, maybe because it is saying that in shear or crushing strength calculations, the term of no.of rivet per pitch 'n' comes and it is the same for anyone of those calculation.
Nadeem afaque said:
6 years ago
It's absolutely right because each rivet in shear is accompanied by crushing on the surface of the body (shank).
Srinivasulu v said:
7 years ago
When rivets are unable to shear of in tensile load they are under in crushed due to this rivet hole becomes of an oval shape. Due to this, no of rivets under shear shall be equal to the no of rivets under crushing.
Arvind Kumar Madheshiya said:
8 years ago
We can not correlate these two. Because the shear and crushing strength will vary material to material.
(1)
Abhi said:
9 years ago
Can anyone prove it in mathematically?
Shubham mamdyal said:
9 years ago
Generally crushing stress is twice of yield stress and shear stress is half of yield stress.
So, the rivets must be twice.
So, the rivets must be twice.
Ameet said:
10 years ago
The shear and crushing forces will be different. How can we relate with no. of rivets?
(1)
Abhishek lunge said:
1 decade ago
Because, the number of rivet remain same on workpiece when you are going to calculate the strength.
Uday cheryala said:
1 decade ago
It's absolutely right because each rivet in shear, is accompanied by crushing on the surface of body (shank).
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