Mechanical Engineering - Machine Design - Discussion

Discussion Forum : Machine Design - Section 1 (Q.No. 47)
47.
Two shafts A and B under pure torsion are of identical length and identical weight and are made of the same material. The shaft A is solid and the shaft B is hollow. We can say that
shaft B is better than shaft A
shaft A is better than shaft B
both the shafts are equally good
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Ganeshr said:   4 years ago
Here B can transmit more power/torque than A.
(1)

Ganiyu Bashir said:   1 decade ago
Shaft B is better probably because it saves cost and material used.

Don said:   1 decade ago
May be but here two shafts under pure torsion so solid shaft better than hollow shaft because it will resist more torsion than hollow shaft.

Abanoub said:   1 decade ago
The question didn't determine the point of comparison between the two shafts.

Hardik patel said:   1 decade ago
As the area of resisting the load in hollow shaft will reduce and in solid shaft will very high so pressure acting upon the solid shaft is less as compared to hollow so it is safe.

Anjana said:   1 decade ago
In qn base for comparison is not given, for cost point of view hollow is best, but in case of maximum load carrying capacity and resist the torsion the solid shaft is better.

Saikumar said:   1 decade ago
Natural frequency is higher for hollow shaft with same weight. Strength of hollow shaft is higher with same weight. Stiffness is more for hollow shaft with same.

Muttinagouda raviraj said:   1 decade ago
A is better than B. Because as the area of cross section increases stress acting on material can distributed stress to entire area. And it has ability to resist the applied load.

Turkish mechanical engineer said:   1 decade ago
If they have same weight and same length that means they have same area of cross section. But shaft with hollow is better because it has more J (polar second moments of area) which is important on shearing load.

Shalabh Suradhaniwar said:   1 decade ago
Shear Stress inversely proportional to J.

J in hollow = Pi*(Do-Di)4/32.

J less, so hollow can bear more Torsion.

J in solid = Pi*(Do)4/32.

J more, so solid can bear less Torsion.


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