Mechanical Engineering - Industrial Engineering and Production Management - Discussion
Discussion Forum : Industrial Engineering and Production Management - Section 2 (Q.No. 6)
6.
A PERT network has three activities on critical path with mean time 3, 8 and 6 and standard deviations 1, 2 and 2 respectively. The probability that the project will be completed in 20 days is
Discussion:
27 comments Page 3 of 3.
Mastan said:
6 years ago
@All.
Here standard deviation means "sigma".
Here standard deviation means "sigma".
(1)
Kapilkotadiya said:
6 years ago
It is working on the function of Z which is denoted by Z(1)=0.84, therefore the answer is 0.84.
Thanks.
Thanks.
Midhunlal said:
6 years ago
Standard deviation equal to square root of variance. Sahir standard deviation is given directly so no need to take root.
Amrit kshetri said:
6 years ago
But PERT network follows beta probability distribution. So can concept of normal distribution curve be applied here?
Debaduyti Nath said:
5 years ago
Agree @Chigumbura and @Uchiha.
In PERT analysis, the time estimates of activities and probability of their occurrence follow Bet Distribution Curve.
But Expected project duration generally follows the Normal Distribution Curve.
The answer is 0.84.
In PERT analysis, the time estimates of activities and probability of their occurrence follow Bet Distribution Curve.
But Expected project duration generally follows the Normal Distribution Curve.
The answer is 0.84.
Shahid Shafi said:
3 years ago
Here, 20-17/5 = 0.66.
Chandu said:
2 years ago
Z = (20-17)/√(1²+2²+2²),
Z = (20-17)/3,
Z = 1,
So P(1)= 0.842.
Z = (20-17)/3,
Z = 1,
So P(1)= 0.842.
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