Mechanical Engineering - IC Engines and Nuclear Power Plants - Discussion
Discussion Forum : IC Engines and Nuclear Power Plants - Section 3 (Q.No. 50)
50.
A gas engine has a swept volume of 300 cm3 and clearance volume of 25 cm3. Its volumetric efficiency is 0.88 and mechanical efficiency is 0.90. The volume of the mixture taken in per stroke is
Discussion:
8 comments Page 1 of 1.
Aman prajapati said:
1 decade ago
Actual volume = swept vol*volumetric efficiency.
= 300*0.88.
= 264 cm3.
= 300*0.88.
= 264 cm3.
Sachin Dhangekar said:
9 years ago
Volume of the mix taken in per stroke = swept vol * volumetric efficiency.
= 300 * 0.88 = 264 cm3.
= 300 * 0.88 = 264 cm3.
Amit+puja said:
1 decade ago
Volume of the mix taken in per stroke = swept vol*volumetric efficiency = 300*0.88 =264 cm3.
Madhu said:
6 years ago
Volumetric efficiency = volume of mix taken per stroke/swept volume.
.88 = v/300,
v = 264.
.88 = v/300,
v = 264.
Keno Teshome said:
8 years ago
Actual volume = swept rvol*volumetric efficiency.
= 300*0.88.
= 264 cm3.
= 300*0.88.
= 264 cm3.
GOUTAM SIK said:
7 years ago
Act vol = sweet vol * volumetric.
Then, = 300*0.88,
= 264cm3.
Then, = 300*0.88,
= 264cm3.
Sushil Kumar Gupta said:
6 years ago
Here, Actual volume = 0.88*300=264 cm3.
(2)
GAURAV said:
6 years ago
Thanks all.
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