Mechanical Engineering - IC Engines and Nuclear Power Plants - Discussion
Discussion Forum : IC Engines and Nuclear Power Plants - Section 1 (Q.No. 5)
5.
The thermal efficiency of a standard Otto cycle for a compression ratio of 5.5 will be
Discussion:
20 comments Page 1 of 2.
Rathod Shwetketu said:
1 decade ago
Formula for finding efficiency is
= 1 - (1/C.R)^0.4
So answer will be near about 49% so its ~50%.
= 1 - (1/C.R)^0.4
So answer will be near about 49% so its ~50%.
Manikandan said:
1 decade ago
Is the Formula varies for Petrol and diesel engine.
Ashutosh kumar said:
1 decade ago
Efficiency of otto cycle is 1-(1/r^y-1).
Where r is the compression ratio : volume before compression to volume after compression and y is the ratio of specific heats which is for air is 1.4.
Where r is the compression ratio : volume before compression to volume after compression and y is the ratio of specific heats which is for air is 1.4.
SHRAVANI said:
1 decade ago
Otto cycle efficiency n(neta)=1-(1/(r^(y-1)).
Compression ratio r=5.5.
T.E=1-(1/((5.5^(1.4-1))).
=0.4943.
=50%.
Compression ratio r=5.5.
T.E=1-(1/((5.5^(1.4-1))).
=0.4943.
=50%.
Zammu said:
1 decade ago
Otto cycle efficiency n(neta)=1-(1/(r^(y-1)).
Compression ratio r=5.5.
T.E = 1-(1/((5.5^(1.4-1))).
= 0.4943.
= 50%.
Compression ratio r=5.5.
T.E = 1-(1/((5.5^(1.4-1))).
= 0.4943.
= 50%.
ANAND SINGH said:
1 decade ago
Efficiency of Otto cycle is : 1-1/Rc^(y-1).
Ajay said:
1 decade ago
This is only approximately you can't calculate actual.
Shikha said:
1 decade ago
For si engine this Otto cycle is defined.
Ravibhange said:
1 decade ago
This is only approximately you can't calculate actual but it is nearly equal to 50%.
Shankar said:
1 decade ago
When using of calculator only you will calculate other wise you not calculate.
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