Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 4 (Q.No. 42)
42.
The hydraulic mean depth for a circular pipe of diameter (d) is
Discussion:
4 comments Page 1 of 1.
Athul M said:
5 years ago
Hydraulic mean depth = area of flow/wetted perimeter.
So in this case, (circular dia=d).
Area = π r^2.
Perimeter = 2 π r.
On dividing we get;
r/2= d/4.
So in this case, (circular dia=d).
Area = π r^2.
Perimeter = 2 π r.
On dividing we get;
r/2= d/4.
Muhammad Waqas said:
9 years ago
Hydraulic mean depth = area of the flow/wetted perimeter.
= (π * r^2)/2* Π * r.
= r/2,
= d/4,
As, r = d/2.
= (π * r^2)/2* Π * r.
= r/2,
= d/4,
As, r = d/2.
(1)
Jaysukh said:
9 years ago
Hydraulic mean depth = area of the flow/wetted perimeter,
M = d^2/4(d),
= d/4.
M = d^2/4(d),
= d/4.
Siva Kumar G said:
9 years ago
Here, the value doesn't change for running full or half.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers