Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 27)
27.
The discharge over a triangular notch is
Discussion:
3 comments Page 1 of 1.
Virendra yadav said:
5 years ago
Thank you @Shiva.
Pksrt said:
8 years ago
Thank you @Shiva.
Shiva said:
1 decade ago
Triangular notch:
Q = (8/15)*Cd*(sqrt(2g))*tan(0/2)*(H)^(5/2).
Rectangular notch:
Q= (2/3)*Cd*b*(sqrt(2g))*(H)^(3/2).
Stepped notch:
Q1= (2/3)*Cd*b1*(sqrt(2g))*(H1)^(3/2).
Q2= (2/3)*Cd*b2*(sqrt(2g))*(((H2)^(3/2))-((H1)^(3/2))).
Q=Q1+Q2+............
Trapezoidal notch:
Q=(Qtri)+(Qrect)=(8/15)*Cd*(sqrt(2g))*tan(0/2)*(H)^(5/2)
+ (2/3)*Cd*b*(sqrt(2g))*(H)^(3/2).
Q = (8/15)*Cd*(sqrt(2g))*tan(0/2)*(H)^(5/2).
Rectangular notch:
Q= (2/3)*Cd*b*(sqrt(2g))*(H)^(3/2).
Stepped notch:
Q1= (2/3)*Cd*b1*(sqrt(2g))*(H1)^(3/2).
Q2= (2/3)*Cd*b2*(sqrt(2g))*(((H2)^(3/2))-((H1)^(3/2))).
Q=Q1+Q2+............
Trapezoidal notch:
Q=(Qtri)+(Qrect)=(8/15)*Cd*(sqrt(2g))*tan(0/2)*(H)^(5/2)
+ (2/3)*Cd*b*(sqrt(2g))*(H)^(3/2).
(3)
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