Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 5 (Q.No. 24)
24.
If the coefficient of discharge is 0.6, then the discharge over a right angled notch is
Discussion:
8 comments Page 1 of 1.
Ganeshr said:
5 years ago
@Munendra.
Value of g is 9.81m/s^2.
Value of g is 9.81m/s^2.
Ankit Singh said:
6 years ago
Discharge through a triangular notch or weir (Q)=8/15*Cd*√(2g)*tanθ/2*H^(5/2)
Cd=Coefficient of discharge.
For right angle V notch or Weir"Cd=0.6 &=90°(Also Cd given in question)
tanθ/2=tan 90°/2=tan 45°=1
So Now,
Q=8/15*Cd*√(2g)*H^(5/2).
On putting Cd=0.6 , g=9.8 in above equation".
Q=1.417H^(5/2).
Cd=Coefficient of discharge.
For right angle V notch or Weir"Cd=0.6 &=90°(Also Cd given in question)
tanθ/2=tan 90°/2=tan 45°=1
So Now,
Q=8/15*Cd*√(2g)*H^(5/2).
On putting Cd=0.6 , g=9.8 in above equation".
Q=1.417H^(5/2).
Munendra said:
6 years ago
@Harsh Shukla.
Then What is the value of "g"?
Then What is the value of "g"?
Yash rajput said:
6 years ago
@Harsh Shukla.
Explained well. Thanks.
Explained well. Thanks.
Harsh Shukla said:
7 years ago
8/15 * C * [(2g)^1/2] * (H^5/2).
C = coefficient of discharge.
C = coefficient of discharge.
Nani said:
9 years ago
Formula 8/15*(2g)^0.5*tan45*-h^2.5*cd (co.efficient of discharge).
Joshua said:
9 years ago
Can you explain clearly with terms?
Bharat said:
1 decade ago
Formula 8/15*tan(O/2)*(2g)^0.5*h^2.5.
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