Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 7)
7.
The discharge over a right angled notch is (where H = Height of liquid above the apex of notch)
Cd 2g x H Cd 2g x H3/2 Cd 2g x H2 Cd 2g x H5/2Discussion:
14 comments Page 1 of 2.
Vikas said:
5 years ago
For the given options, this answer can be found easily using dimensional analysis, as discharge = m3/sec.
(1)
Anupama said:
7 years ago
Please explain it briefly.
A.RASAKUMAR said:
7 years ago
How to solve it? please explain.
Hari said:
8 years ago
Cd is the cofficient of discharge. It is used as correction factor.
Anuj said:
8 years ago
Q = 8/15*Cd*tan(@/2)* root2*h*Hpower 5/2.
Hibistu said:
8 years ago
How can I solve it? Please explain in detail.
Pravalika said:
9 years ago
For triangular v notch, discharge=8/15 √2g (tanteta/2) h^(5/2) Cd.
For a right angled θ =90 substitute in it and get answer.
For a right angled θ =90 substitute in it and get answer.
Kumar said:
9 years ago
How to know this?
Rohit rakte said:
1 decade ago
After the Br equation we can call discharge it is stranded formula?
RAKESH KUMAR said:
1 decade ago
Cd means Coefficient of discharge.
It is between of contact of water and perpendicular axis is called angle of apex of notch.
It is between of contact of water and perpendicular axis is called angle of apex of notch.
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