Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 3 (Q.No. 48)
48.
The length AB of a pipe ABC in which the liquid is flowing has diameter (d1) and is suddenly contracted to diameter (d2) at B which is constant for the length BC. The loss of head due to sudden contraction, assuming coefficient of contraction as 0.62, is
Discussion:
10 comments Page 1 of 1.
Dipnkr said:
1 decade ago
(1-(1/c))'2*(v'2/2g).
Kuru said:
10 years ago
How it is possible my dears?
K V N N Ravi Tej said:
10 years ago
Because loss of head due to contraction= ((v2*2)/2g)((1/c)-1)*2).
Sumit said:
8 years ago
Head loss due to contraction is 0.5v2^2/2g.
Lipu said:
8 years ago
Loss if head due to sudden contraction(hc)=Kv^2/2g.
Where k=coefficient of contraction.
So, the answer should be hc=0.62*v2^2/2g=0.31v2^2/2g.
If coefficient of contraction is not given then answer will be 0.5v2^2/2g.
Where k=coefficient of contraction.
So, the answer should be hc=0.62*v2^2/2g=0.31v2^2/2g.
If coefficient of contraction is not given then answer will be 0.5v2^2/2g.
Subhrasis nayak said:
8 years ago
(hl)=v2^2/2g*((1/cc)-1)^2.
So, (hl)=v2^2/2g*((1/0.62)-1)^2,
(hl)=v2^2/2g*0.375.
So, (hl)=v2^2/2g*((1/0.62)-1)^2,
(hl)=v2^2/2g*0.375.
Harsh Shukla said:
6 years ago
Head loss due to sudden contraction = [{1/c - 1}^2] * [v2^2/2g].
c = 0.62.
c = 0.62.
MD MOSHAHID HUSSAIN said:
6 years ago
LOSS OF HEAD DUE TO SUDDEN CONTRACTION = V2^2/2g[ (1/Cc) -1].
Putting the value Cc=0.62, we get 0.375* V2^2/2g.
Putting the value Cc=0.62, we get 0.375* V2^2/2g.
Gurudas said:
5 years ago
Hs.c = [{V2^2/2g} * {(1/Cc)-1}^2].
= (V2^2/2g) * [{(1/0.62)-1}^2].
= (V2^2/2g) * 0.375.
= (V2^2/2g) * [{(1/0.62)-1}^2].
= (V2^2/2g) * 0.375.
Pritesh mahajan said:
4 years ago
Loss of head due to sudden contraction = V2^2/2g*(1/Cc-1)^2.
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