Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 5 (Q.No. 44)
44.
A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be
Discussion:
1 comments Page 1 of 1.
M.S.R said:
7 years ago
Here, vol/time = a* √(2g(H2-H1).
time = A(H1-H2) /(a*√(2g(H1-H2)).
Now, time = A* √(H1-H2)/Cd*a*√(2g).
Correct me if I am wrong.
time = A(H1-H2) /(a*√(2g(H1-H2)).
Now, time = A* √(H1-H2)/Cd*a*√(2g).
Correct me if I am wrong.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers