Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 20)
20.
The discharge through a large rectangular orifice is given by (where H1 = Height of the liquid above the top of the orifice, H2 = Height of the liquid above the bottom of the orifice, b = Breadth of the orifice, and Cd = Coefficient of discharge)
Q = 
Cd x b2g(H2 - H1)
Cd x b2g(H2 - H1)Q = Cd x b2g(H21/2 - H11/2)
Cd x b2g(H21/2 - H11/2)Q = Cd x b2g(H23/2 - H13/2)
Cd x b2g(H23/2 - H13/2)Q = Cd x b2g(H22 - H12)
Cd x b2g(H22 - H12)Discussion:
5 comments Page 1 of 1.
Mukesh said:
8 years ago
Explain the solution, Please.
Shruti said:
8 years ago
When d is very small compared to H1 & H2, dQ= cv B d √( 2 gh), then by integrating Q= 2/3 cv B d √(2g) H2^(3/2)-H1^(3/2).
Mahati said:
7 years ago
@Shruti.
Can you please explain it briefly.
Can you please explain it briefly.
Sid said:
6 years ago
Direct formulae.
For rectangular orifice{Q}= 2/3Cd*b*√2g*(H2^3/2 - H1^3/2),
For fully submerged orifice (Q) = Cd*b*(H2 +H1)*√2gh.
For partially submerged orifice = sum of the above.
For rectangular orifice{Q}= 2/3Cd*b*√2g*(H2^3/2 - H1^3/2),
For fully submerged orifice (Q) = Cd*b*(H2 +H1)*√2gh.
For partially submerged orifice = sum of the above.
Pratik Devendra Khirade said:
5 years ago
Thanks @Sid.
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