Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 9)
9.
A vertical wall is subjected to a pressure due to one kind of liquid, on one of its sides. The total pressure on the wall per unit length is (where w = Specific weight of liquid, and H = Height of liquid)
Discussion:
21 comments Page 1 of 3.
Jitendra Khemani said:
6 years ago
Total Pressure = rho*g*H*A.
Total pressure/lenth = (rho*g*H*A)/l.
H = h/2.
Then,
= (rho*g*h*A) / 2l (A= h*l)
= (rho*g*h*h*l) / 2l.
= (rho*g*h^2) / 2.
= (w*h^2) / 2 ( specific weight (w) = rho*g).
Total pressure/lenth = (rho*g*H*A)/l.
H = h/2.
Then,
= (rho*g*h*A) / 2l (A= h*l)
= (rho*g*h*h*l) / 2l.
= (rho*g*h^2) / 2.
= (w*h^2) / 2 ( specific weight (w) = rho*g).
(10)
Poggir said:
5 years ago
Total Pressure = ρ*g*H*A.
This formula is for total force right?
This formula is for total force right?
(1)
Ram said:
5 years ago
@Jitendra.
Total pressure or force? Please explain.
Total pressure or force? Please explain.
(1)
Hardeep said:
7 years ago
But the position of the centre of pressure will be 2/3 of h.
So, the answer should be 2/3wh^2.
So, the answer should be 2/3wh^2.
(1)
Gourav said:
7 years ago
Please explain this clearly to understand.
Dev said:
3 years ago
Good explanation @Jitendra Khemani.
Rajkotha said:
4 years ago
Pressure intensity = wh.
Total pressure = wH^2/2.
Total pressure = wH^2/2.
Umer said:
5 years ago
For finding pressure per unit of length,
P = W*H.
Where we are finding pressure effect on unit length,
So, H = Integral H dh.
H = H^2/2.
So,
P = w * H.
P = wH^2/2.
P = W*H.
Where we are finding pressure effect on unit length,
So, H = Integral H dh.
H = H^2/2.
So,
P = w * H.
P = wH^2/2.
Abhi said:
5 years ago
@Poggir
Yes, the formula for total pressure is F= ρ*g*A*h.
Yes, the formula for total pressure is F= ρ*g*A*h.
Banny said:
5 years ago
Good explanation @Jitendra.
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