Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 8 (Q.No. 2)
2.
The pressure at a point 4 m below the free surface of water is
Discussion:
3 comments Page 1 of 1.
Sivaramireddy said:
1 decade ago
Pressure= density*g*h.
= 1000*9.81*4.
= 39240 pascal or 39.2kpa.
= 1000*9.81*4.
= 39240 pascal or 39.2kpa.
(2)
Jnk said:
9 years ago
Pressure = 9.81 * 4= 39.2.
(1)
SRAVAN said:
7 years ago
Thanks @Sivaramiredy.
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